scoring in mixed medalford&stableford

Hello everyone,If a comp. consists of medalford for the first 9 holes and stableford scoring for the back 9 holes,using full handicap,it is my understanding that for an even number handicap ie.2,4,6,8,10 etc,half the handicap is deducted from the gross medalford score,the remainder used to calculate the stableford points.What is the procedure for an uneven number handicap ie.1,3,5,7,9 etc.Is it correct to say eg.19 handicap,9 strokes be deducted from the gross medalford,and the remaining 10 used for stableford purposes?,or 11 handicap,reulting in 5 medalford and 6 stableford.? Thanks,springbok.

My guess would be that if you had an 11 handicap you would get a stroke on the 11 hardest holes. (according to the score card) Most courses that would equate to 6 on one side and 5 on the other and the extra stroke ends up on the hardest 9.

Bob

hello ogallalabob,thanks for replying.If I may expand on my question.In the competition I was referring to,the front nine holes nett score - the stableford points scored= the winnner.It is one of the formats for a friendly comp.amongst say twenty members.So to illustrate,eg an 18 handicapper would have his gross score on the first 9 holes less 9.This is his nett score for the medalford format of the comp.For the back 9 holes,he would be be allowed a stroke for each hole,which would result in a score ie.1 under par=3pts,par=2pts,1 over par=1pt.The player would then add up his total of stableford points,subtract this number from the nett medalford format.The player with the lowest number is the winner.My question is,how would you split the handicap of an uneven number.In the case of say an 19 handicap player,is it correct to apply 9 strokes to the medalford format and 10 strokes to the stableford format,or in the case of say an 11 handicapper,would you then apply5 to the medalford and 6 to the stableford. I would appreciate your comments.

hello ogallalabob,thanks for replying.If I may expand on my question.In the competition I was referring to,the front nine holes nett score - the stableford points scored= the winnner.It is one of the formats for a friendly comp.amongst say twenty members.So to illustrate,eg an 18 handicapper would have his gross score on the first 9 holes less 9.This is his nett score for the medalford format of the comp.For the back 9 holes,he would be be allowed a stroke for each hole,which would result in a score ie.1 under par=3pts,par=2pts,1 over par=1pt.The player would then add up his total of stableford points,subtract this number from the nett medalford format.The player with the lowest number is the winner.My question is,how would you split the handicap of an uneven number.In the case of say an 19 handicap player,is it correct to apply 9 strokes to the medalford format and 10 strokes to the stableford format,or in the case of say an 11 handicapper,would you then apply5 to the medalford and 6 to the stableford. I would appreciate your comments.